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| Direktori : /snap/certbot/5911/lib64/python3.12/site-packages/setuptools/_distutils/compilers/ |
| Current File : //snap/certbot/5911/lib64/python3.12/site-packages/setuptools/_distutils/compilers/_util.py |
"""Small stdlib-only utilities used across the compilers package."""
from __future__ import annotations
import re
import string
# Needed by 'split_quoted()'
_wordchars_re = re.compile(rf'[^\\\'\"{string.whitespace} ]*')
_squote_re = re.compile(r"'(?:[^'\\]|\\.)*'")
_dquote_re = re.compile(r'"(?:[^"\\]|\\.)*"')
def split_quoted(s: str) -> list[str]:
"""Split a string up according to Unix shell-like rules for quotes and
backslashes. In short: words are delimited by spaces, as long as those
spaces are not escaped by a backslash, or inside a quoted string.
Single and double quotes are equivalent, and the quote characters can
be backslash-escaped. The backslash is stripped from any two-character
escape sequence, leaving only the escaped character. The quote
characters are stripped from any quoted string. Returns a list of
words.
"""
# This is a nice algorithm for splitting up a single string, since it
# doesn't require character-by-character examination. It was a little
# bit of a brain-bender to get it working right, though...
s = s.strip()
words = []
pos = 0
while s:
m = _wordchars_re.match(s, pos)
assert m is not None
end = m.end()
if end == len(s):
words.append(s[:end])
break
if s[end] in string.whitespace:
# unescaped, unquoted whitespace: now
# we definitely have a word delimiter
words.append(s[:end])
s = s[end:].lstrip()
pos = 0
elif s[end] == '\\':
# preserve whatever is being escaped;
# will become part of the current word
s = s[:end] + s[end + 1 :]
pos = end + 1
else:
if s[end] == "'": # slurp singly-quoted string
m = _squote_re.match(s, end)
elif s[end] == '"': # slurp doubly-quoted string
m = _dquote_re.match(s, end)
else:
raise RuntimeError(f"this can't happen (bad char '{s[end]}')")
if m is None:
raise ValueError(f"bad string (mismatched {s[end]} quotes?)")
(beg, end) = m.span()
s = s[:beg] + s[beg + 1 : end - 1] + s[end:]
pos = m.end() - 2
if pos >= len(s):
words.append(s)
break
return words
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